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# question: a bullet of mass 10g moving with velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900g.What is the velocity acquired sejak the block?

the first person who gives the right answer with reasons would get 100 pujian and the others would get 40 pujian for participating! so good luck!
6 hours!! this soalan would get closed.
fightxd posted hampir setahun yang lalu fightxd posted hampir setahun yang lalu
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## Science Jawapan demi382 said: answer:4.4m/s reason: let the final velocity of the bullet embedded in it be v according to the law of conservation of momentum, total momentum before collision = total momentum after collision = 0.001* 400+0.9*0/0.001 + 0.9 = 4/0.91 = 400/91 = 4.4 m/s posted hampir setahun yang lalu
correct answer but i can't belive that no one answered than anda , any way congratulations!
fightxd posted hampir setahun yang lalu bahu said: mass of bullet= 10 g = 0.01 kg velocity of bullet=400 m/s mass of wooden box= 900 g =0.9 kg velocity of wooden block= ? formula= Mb 1*Vb 1=Mb 2*Vb 2 0.01*400=0.9*Vb2 =0.01*400/0.9=4.4444444 m/s ans=4.4 m/s posted hampir setahun yang lalu